ECET 110 Week 5 Homework

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ECET 110 Week 5 Homework Click Below Link To Purchase www.foxtutor.com/product/ecet-110-week-5-homework CHAPTER 9 1a. Using the superposition theorem, determine the current through the 12 Ohm resistor of fig. 9.119. we will use superposition to analyze this circuit. First short E2 and find the current thru the 12 Ohms resistor and then Short E1 and keep E2 in the circuit and find the same current. Then algebraically add the two currents (add if in the same directions and subtract if opposite direction Short V2 12Ohms resistor—IR3 IR1 and IR3 are the same value IR3=4A Short V1 12 Ohms resistor—IR3 IR3=5A Subtract the values due to opposing directions IR3=IR3(V1)+IR3(V2)=5A-4A=1A 1b. Convert both voltage sources to current sources and recalculate the current to the 12 Ohm resistor. Subtract the two current sources (because they are opposite directions) and the result will be one current source. You can find individual currents using current divider rule 1c. How do the results of parts a and b compare? The answers are to be the same.

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ECET 110 Week 5 Homework Click Below Link To Purchase www.foxtutor.com/product/ecet-110-week-5-homework CHAPTER 9 1a. Using the superposition theorem, determine the current through the 12 Ohm resistor of fig. 9.119. we will use superposition to analyze this circuit. First short E2 and find the current thru the 12 Ohms resistor and then Short E1 and keep E2 in the circuit and find the same current. Then algebraically add the two currents (add if in the same directions and subtract if opposite direction Short V2 12Ohms resistor—IR3 IR1 and IR3 are the same value IR3=4A Short V1 12 Ohms resistor—IR3 IR3=5A Subtract the values due to opposing directions IR3=IR3(V1)+IR3(V2)=5A-4A=1A 1b. Convert both voltage sources to current sources and recalculate the current to the 12 Ohm resistor. Subtract the two current sources (because they are opposite directions) and the result will be one current source. You can find individual currents using current divider rule 1c. How do the results of parts a and b compare? The answers are to be the same.

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