Quadratic Equation Calculator

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Quadratic Equation Calculator Quadratic equation is a polynomial equation which is in the form of Ax2 + Bx + C = 0(second degree). Quadratic Equation Calculator  is an online tool to solve a quadratic quad ratic equation. It

makes calculation easy and fun.

If any quadratic equation is given then it can easily find factors of that equation. Try our Quadratic Equation Calculator and get your problems solved instantly.

Steps to Solve the Quadratic Equation Step 1 :-  Observe the value of a, b and c from the quadratic equation. Step 2 :-  Find the value of discriminant(D) by applying the formula D = b2 - 4ac.  

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Step 3 :-   If the value of discriminant is less than zero, write "roots "roots does not exist/

imaginary. And if discriminant is greater or equal to zero, then find the roots of an equation by applying the formula x1= −b+D√2a and x2= −b−D√2a Examples on Quadratic Equation Calculator

Find the roots of an equation x2 + 7x + 12 = 0? Step 1 :-  Here a = 1, b = 7, c = 12 Step 2 :-  D = b2 - 4ac = 72 - 4 × 1 × 12 = 49 - 48

D=1 Step 3 :-  x1 = −b+D√2a −b+D√2a = −7+1√2×1 = −62 = -3

  x2 = −b−D√2a = −7−1√2×1 = −82 = -4 Answer :-  x1 = -3

x2 = -4

Find the root of an equation x2 + 4x + 5 = 0? Step 1 :-  Here a = 1, b = 4, c = 5 D = -4 Step 2 :-  D = b2 - 4ac = 42 - 4 × 1 × 5 = 16 – 20, imaginary, since discriminant is less than zero. Step 3 :-  Roots are imaginary,   Answer :-  Roots are imaginary

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Factorizing Trinomials In this article, we study about Factoring Trinomials. Trinomials are defined in Mathematics an expression containing 3 unlike terms. For example, xz+y-2 is a trinomial, whereas x2-3X-X is not a trinomial as this can be simplified in to a binomial. So for an expression to be a trinomial, we have 3 terms  which cannot be further simplified. The degree of the trinomial is the highest degree in the expression. If the highest degree of all variables put together is 2 then it is called quadratic and if it is 3, then it is cubic function. Factoring trinomials is complicated than factoring numbers because numbers are all like terms, which we can add , subtract, etc. Also numbers we are familiar with tables and know the divisibility rules for 2,3, 9, etc. But for expressions also we can become well-versed by continuous practice and doing   exercises

Understanding the concept of factoring trinomials whenever it is of a square form, or  whether +ve sign is there, or -ve sign is there, if we understand then factorization will be one step further. The advantage of trinomial is that its degree normally does not exceed 2. Hence quadratic formula we can apply if we cannot find exact splitting up of the x term. Eg :- x2-2x-1 is of degree 2 whereas x4-x2-1 is a trinomial of degree 4.

Factoring trinomials can be done in any of the following ways. We already know these identities as (a+b)2 = a2+2ab+b2

(a-b)2 = a2-2ab+b2

(x+a)(x+b) = x2+x(a+b)+ab

These can be applied in reverse to factoring trinomials of this form. Example :- Factorize x2-6x+9

This is of the form x2-2(x)(3)+32 . So factors are (x+3)2 Next is factorise 25x2-50x+1 = (5x)2-2(5x)(1)+1 = (5x-1)2 Thus these type of terms can be easily factored. Hence given a polynomial we check  whether it is a quadratic with on variable, if it is so, check whether first term and last term is a square.  

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If it is satisfied then check for middle term whether it is of the form 2ab. Thus this identity in reverse is used in factoring trinomials, For expressions of the form say x2-6x+5 , we have 5=5*1, and 6 =5+1, thus the third identity can be applied here to factorize. So the expression = (x-5)(x-1). Thus these three identities are helpful in Factoring trinomials.

How to Factor Trinomials Students can learn tolines. Factor Trinomials from the application of the formula and solving problems on How similar  = 1.   Factoring trinomials Example : i. x2-3x-4: Here we have - sign for ab. So for -4 we

must have two factors such that their sum if -3. -4=-4*1, -4+1=-3. So we can factorise as (x-4)(x+1). 2.  Factoring trinomials Example of x2+7x-30. In this problem, ab =-30, and their sum is

+7. So suitable factors are -10 *3 = -30. So answer is (x+10)(x-3).   trinomials Example of the type: where a gcf is there. 3. Factoring

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