CAT 2008 Solutions Part - 3 - CAT 2013

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8/12/2014 CAT 2008 Solutions Part - 3 - CAT 2013
http://cat.learnhub.com/lesson/6656-cat-2008-solutions-part-3 1/14
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CAT 2008 Solutions Part - 3
by Suresh
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Section - II (DI/Logical Ability)
Directions for Questions 26 to 28: Answer the following questions based on the statements given below:
1. There are three houses on each side of the road.
2. These six houses are labeled as P, Q, R, S, T and U.
3. The houses are of different colours,namely,Red,Blue,Green,Orange, Yellow and White.
4. The houses are of different heights.
5. T, the tallest houese, is exactly opposite to Red coloured house.
6. The shortest house is exactly opposite to the Green Coloured house.
7. U, the Orange coloured houese, is located between P and S
8. R, the yellow coloured house, is exactly opposide to P.
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9. Q, the green coloured house, is exactly opposide to U
10. P, the white coloured houese, is taller than R,but shorter than S and Q.
Q.26. What is the colour of the house diagonally opposite to the Yellow coloured house?
(1) White
(2) Blue
(3) Green
(4) Red
(5) None of these
Note From Statements (VII), (VIII) and (IX), we get.
Then, T is opposite S and the colour of S is red. From (x), the colour of house P is white, hence the colur of house T
is blue.
Now, From (v) and (x),we get
T > S, Q > P > R
From (VI), U is the shorest.
i.e., the order of houses in the decending order of their heights is T, S/Q, Q/S, P, R, U.
Ans. R is yellow coloured house and the house diagonally opposite R is S. and the color of house S is Red. Hence,
4
.
Q.27. Which is the second tallest house?
(1) P
(2) S
(3) Q
(4) R
(5) Can not be determind
Ans. The second tallest house is either S and Q. Hence,
5
.
Q.28. What is the colour of the tallest house ?
(1) Red
8/12/2014 CAT 2008 Solutions Part - 3 - CAT 2013
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(2) Blue
(3) Green
(4) Yellow
(5) None of these
Ans. The tallest house is T and its colour is blue. Hence,
2
Directions for Questions 29 to 31: Answer the following questions based on the statements given below:
Telecom operators get revenue from tranfer of data and voice. Average revenue received from tranfer of each unit of
data is known as ARDT. In the diagram below, the revenue received from data transfer as percentage of total
revenue received and the ARDT in US Dollors(USD) are given for various countries.
Q.29. It was found that the volume of data transfer in India is the same as that of Singapore. Then which of the
following statements is true?
(1) Total revenue is the same in both countries
(2) Total revenue in India is about 2 times that of Singapore
(3) Total revenue in India is about 4 times that of Singapore
(4) Total revenue in Singapore is about 2 times that of India
(5) Total revenue in Singapore is about 4 times that of India
Ans. Let the volume of data is India and Singapore be y, each then


Hence,
5
Q.30. It is expected that by 2010, revenue from india data tranfer as a percentage of total revenue will triple for
India and double for Sweden. Assume that in 2010, the revenue in India is twice that of Sweden and that the
8/12/2014 CAT 2008 Solutions Part - 3 - CAT 2013
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volume of data transfer is the same in both the countries. What is the percentage increase of ARDT in india if there
is no change in ARDT is Sweden?
(1) 400 %
(2) 550 %
(3) 800% %
%{font-family:verdana;font-size:13px}(4) 950 %
(5) Cannot be determind
Ans. Revenue from data tranfer as percentage of total revenue in 2010
Total revenue in 2010
In India= 2 * In Sweden(say x)
In 2010, the volume of the data tranfer in each country be y.
ARDT in Sweden in 2010 =$6 (same in graph)
Let ARDT in India in 2010 be z, then

z= $9
%{font-family:verdana}The required percentage increase%
Hence,
3
Q.31. If the total revenue is the same for tha pairs of countries listed in the chocies below, choose the pair that
has approximately the same volume of data tranfer.
(1) Philippines and Aurtria
(2) Canada and Ploand
(3) Germany and USA
(4) UK and Spain
(5) Denmark and Mexico
Ans. We now that
of toal revenue
i.e. we want a pair for whom the ratio
is approsimately same for both



Hence,
4
8/12/2014 CAT 2008 Solutions Part - 3 - CAT 2013
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Directions for Questions 32 to 34: For admission to various affiliated colleges, a university conducts a written test
with four different sections, each with a maximum of 50 marks. The following table gives the aggregate as well as
the sectional cut-off marks fixed by six different colleges affiliated to the university. A student will get admission
only if he/she gets marks greater than or equal to the cut-off marks in each of the section and his/her aggregate
marks are at least equal to the aggregate cut-off marks as specified by the college.
Q.32. Bhama got calls from all colleges. What could be the minimum aggregate marks obtained by her?
(1) 180
(2) 181
(3) 196
(4) 176
(5) 184
Note. Sectional cut-offs for colleges 1,2,3,4,5 and 6 are mentioned
In the table given in the question
The sections where cut-offs are missing need not be considered
Ans. To get calls from all colleges, Bhama should score marks equal to maximum cut-off marks required for each
section of all the colleges the Bhama should score.
Section ASection B Section CSection D
45 45 46 45
Aggregate marks obtained = 45 + 45 + 45 + 46 = 181.Hence,
2
Q.33. Charlie got calls from two colleges. What could be the minimum marks obtained by him in a section?
(1) 0
(2) 21
(3) 25
(4) 35
(5) 41
Ans. If aggregate marks of Charlie are 175. Charlie stands a chance to clear cut-off of college 2 and 3.
So, Charlie should score.
Section ASection B Section CSection D
50 50 50 25
Aggregate marks obtained = 50 + 50 + 50 +25 = 175 Hence,
3
Q.34. Aditya did not get a call from even a single college. What could be the maximum aggregate marks obtained
by him?
8/12/2014 CAT 2008 Solutions Part - 3 - CAT 2013
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(1) 181
(2) 176
(3) 184
(4) 196
(5) 190
Ans. Aditya did not get a call from even a single college and if he has score maximum aggregate marks, he must
have cleared cut-off of two sections with higest score and not cleared the remaining two, so,
Aditya should have scored
Section ASection B Section CSection D
50 50 41 43
Aggregate marks obtained = 50 + 50 + 41 +43 = 184. Hence,
3
Directions for Questions 35 to 38: Answer the following questions based on the statements given below:
In a sports event, six teams(A, B, C, D, E and F) are competing against each other. Matches are scheduled in two
stages. Each team plays three matches in Stage-I and two matches in Stage-II. No team plays against the same
team more than once in the event. No ties are permitted in any of the matches. The Obsercations after the
completion of Stage-I and Stage-II are as given below:
Stage-I
%{font-family:verdana}One team won all the three matches.%
Two teams lost all the matches
D lost to A but won against C and F
E lost to B but won against C and F
B lost at least one match
F did not play against the top team of Stage-I
Stage-II
%{font-family:verdana}The leader of Stage-I lost the next two matches%
%{font-family:verdana}Of the two teams at the bottom after Stage-I, one team won both matches, while the other lost both matches.%
%{font-family:verdana}One more team lost both matches in Stage-II%
Q.35. The two teams that defeated the leader of Stage-I are
(1) F & D
(2) E & F
(3) B & D
(4) E & D
(5) F & D
Note
Stage I:
B lost at least one match. D and E lost one match each .
C and F have lost two matches each.
i.e A is the top team of Stage I and has won all the three matches in Stage I
8/12/2014 CAT 2008 Solutions Part - 3 - CAT 2013
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Hence, A and F did not play against each other in stage 1.
Also, B D and E have won at least one match.Hence, C and F must have lost all the 3 matches in Stage I.
Thus, the 9 matches played in Stage I are:
D(Won) x C(Lost)
D(Won) x F(Lost)
D(Lost) x A(Won)
E(Lost) x B(Won)
E(Won) x C(Lost)
E(Won) x F(Lost)
A(Won) x B(Lost)
A(Won) x C(Lost)
B(Won) x F(Lost)
Stage II:
The 6 matches played in Stage II are as follows:
A x E
A x F
B x C
B x D
D x E
C x F
The leader of Stage I i.e A lost both his matches.
Two teams at the bottom after stage I and C and F.
Since, F lost againt A, F lost againt C also.
And C won against B and F
Now, the only other team that lost both the matches is D
A(Lost) x E(Won)
A(Lost) x F(Won)
B(Won) x C(Lost)
B(Won) x D(Lost)
D(Lost) x E(Won)
C(Lost) x F(Won)
Ans. 35-
2
Q.36. The only team(S) that won both matches is Stage-II are
(1) B
(2) E & F
(3) A, E & F
(4) B, E & F
(5) B & F
Ans. 36-
4
Q.37. The teams that won exactly two matches in the event are
(1) A, D & F
(2) D & E
(3) E & F
(4) D, E & F
(5) D & F
Ans. 37-
5
Q.38. The teams(s) with the most wins in the event is (are)
(1) A
(2) A & C
8/12/2014 CAT 2008 Solutions Part - 3 - CAT 2013
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(3) F
(4) E
(5) B & E
Ans. 38-
5
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rajesh singh – over 5 years ago
thnx sir
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Venkateswara Reddy.M – over 5 years ago
thanQ sir
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swapana jaiswal – over 5 years ago
thank u sir.
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arun – over 5 years ago
I have searched many other websites for CAT 2008 solutions.
It was learnhub.com, i found them at last!
Keep the goodwork going on ,Sureshbala!!
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harshit_jiya – over 5 years ago
this is very nice
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rajkiran508 – over 5 years ago
nice logical answering by suresh
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zia matin – over 5 years ago
its vry important to us n u r giving us the most helpful thing. we can learn a great deal from this.
thank u
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richa_jain – over 5 years ago
sir, this is very helpful thnxx
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pannu k – over 5 years ago
thnx Suresh..
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Suresh – over 5 years ago
Dear kvin2kool, with the scores mentioned by you Aditya will get admission into all the colleges other than college 3. But in the question it is given that
Aditya did not get a call even from a single college which means he did not get admission from any of the six colleges and I think you have mistaken it for
"did not get a call from one of the colleges".
Regards
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pannu k – over 5 years ago
question 34, for college 3, the marks can be 50 , 50, 45, 50, y is this possibity ruled out ?
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