ECET 375 Week 6 Homework
ECET 375 Week 6 Homework Click Below Link To Purchase www.foxtutor.com/product/ecet-375-week-6-homework Chapter 20-Questions Pg-652-654 20-1: What is the primary purpose of using subnetting? 20-2: List and describe several reasons why network designers create subnetting. 20-3: Explain the differences between default masksandsubnet masks. 20-7: Explain the reasons for using supernetting. Chapter 20-Problems 20-1: What is the default mask for the network address 139.100.0.0? a.255.0.0.0 b.255.255.255.0 c.255.255.0.0 d.255.255.255.255 20-2: Using the default mask, how many hosts can the classful network 109.0.0.0 support? 20-7: How many hosts can be supported on a classful class B network with the following subnetmask: 255.255.224.0? 20-9: You have a host IP address of 40.150.73.10 and a subnet mask 255.248.0.0: 20-15: Determine the subnet addresses and subnet masks for a business network with the classful class C address 204.238.7.0 with six departments having separate subnetworks with the following numbers of hosts: 20-23: A small business has been assigned a classless network address 210.38.4.0. 20-24: Determine the following for the network specified in problem 20-23: Chapter 21-Questions Pg-700-702 21-3: What is the primary purpose of the address resolution protocol (ARP)? Chapter 21-Problems 21-3: Determine the contents of the first byte of an IP header if the IP protocol is IPv4 and the header has 40 bytes of options. 21-6: Determine the length of an ICMP data field for Ethernet frame that is carrying an IP datagram with a 28-byte header and an eight-byte ICMP header and the Ethernet data field is 600 bytes long. 21-7: Use the following network analyzer display of an ARP packet to answer the following questions: 0000 00 07 08 00 06 04 00 02 00 00 BD 41 2A 1C C1 98 0010 A0 14 00 00 40 A3 B1 CC C1 98 0F 10 21-8: Use the following network analyzer display of an IP packet to answer the following questions: 0000 45 28 13 82 01 A2 21 34 F3 01 43 A1 C0 99 4A 01 0010 99 4A 0C -- -- -- -- -- -- -- -- -- -- -- -- -- 21-11: A maximum-length data gram carrying 65,536 bytes can be transported over a WAN with a maximum packet length of 292 bytes, which includes the 20-byte IP header. Determine…
