Sample in Nutrition Computation by EJ

Nutrition computation sample
Anthropometric measures:
Height: 5’4” / 162.56 cm / 1.625m
Actual weight: 59 kg
Medium Frame
Student

Total Energy Expenditure
(rounded off to the nearest 50)
TEE = BMR + PA + SDA
TEE = 1344 kcal + 672 kcal + 134.4 kcal
TEE = 2150.4 Kcal / 2150 kcal

DBW = [height(cm) – 100] – 10%
DBW = [ 162.56 – 100] – 10%
DBW = 62.56 – 10%
DBW = 62.56 – 6.256
DBW = 56.304kg /56Kg

Calculating for Carbohydrate, Protein,
and Fats (nearest 5)
(CHO – 60% CHON – 15% Fats –
25%)

BMI = Actual weight
m2
BMI =
59 kg
(1.65m) 2
BMI = 59 kg
2.64
BMI = 22.3
BMIValue = 22.3
BMICategory = Normal Range
Basal Metabolic Rate
BMR = 1 Kcal x DBW x 24hrs
BMR = 1 Kcal x 56kg x 24hrs
BMR = 1344 Kcal
Physical Activity
Student Activity = 50% PA
PA=BMR x % PA
PA = 1344 kcal x 0.50
PA = 672 Kcal
Specific Dynamic Action
SDA = BMR x 10%
SDA = 1344 x 0.10
SDA = 134.4 Kcal

Carbohydrate = TEE x .60 / 4 kcal/g
Carbohydrate = 2150kcal x .60 / 4 kcal/g
Carbohydrate = 1290kcal / 4 kcal/g
Carbohydrate = 322.5 g / 320.g
Protein = TEE x .15 / 4 kcal/g
Protein = 2150kcal x .15 / 4 kcal/g
Protein =322.5kcal / 4 kcal/g
Protein = 80.625g / 80g
Fats = TEE x .25 / 9 kcal/g
Fats = 2150kcal x .25 / 9 kcal/g
Fats = 537.5kcal / 9 kcal/g
Fats = 59.72g / 60g