Typical Procal Template
Content
FREE FALL CONSIDERED 50mm
Splitter Box to Launder
Flow, Normal
Flow, Design
=
=
260 m3/hr
260 m3/hr
TWL = TOP OF WATER LEVEL
TWL in Splitter box provided
=
Flow, Design to 2 anoxic tank
Flow over weir in the splitter box to Launder
Width of weir , b
Coeff. of discharge, Ce
=
108.74 m
260.00 m3/hr
=
=
2.50 m
0.864
h=(Q/(0.5445*Ce*(g)^0.5*b))^(2/3)
=
0.0727 m
Free fall considered
=
0.05 m
=
108.62 m
Head over weir=
Therefore,
TWL in Splitter Box to Launder
Launder to Anoxic Tank
Flow, Normal
Flow, Design
=
=
TWL in Launder provided
=
Flow, Design to 2 anoxic tank
Flow over weir in the Launder to 2 anoxic tank
Width of weir , b
Coeff. of discharge, Ce
=
260 m3/hr
260 m3/hr
108.62 m
260.00 m3/hr
=
=
0.40 m
0.864
h=(Q/(0.5445*Ce*(g)^0.5*b))^(2/3)
=
0.2467 m
Free fall considered
=
0.05 m
=
108.33 m
Head over weir=
Therefore,
TWL in Launder to 2 Anoxic tanks
Anoxic Tank to Aeration Tank
Flow, Normal
Flow, Design
=
=
TWL in Anoxic Tank provided
=
Flow, Design to Aeration tank
Flow over weir in the Anoxic tank to aeration
Width of weir , b
Coeff. of discharge, Ce
=
330 m3/hr
330 m3/hr
108.33 m
330.00 m3/hr
=
=
7.00 m
0.864
h=(Q/(0.5445*Ce*(g)^0.5*b))^(2/3)
=
0.0429 m
Free fall considered
=
0.05 m
=
108.23 m
Head over weir=
Therefore,
TWL in Anoxic Tank to Aeration Tank
Aeration Tank to Launder
Flow, Normal
Flow, Design
=
=
TWL in Aeration Tank provided
=
Flow, Design to Polimer tank
Flow over weir in the aeration to Launder
Width of weir , b
Coeff. of discharge, Ce
=
660 m3/hr
660 m3/hr
108.23 m
660.00 m3/hr
=
=
6.00 m
0.864
h=(Q/(0.5445*Ce*(g)^0.5*b))^(2/3)
=
0.0755 m
Free fall considered
=
0.05 m
=
108.11 m
Head over weir=
Therefore,
TWL in Aeration Tank to Launder
Launder To Polymer tank
Flow, Normal
Flow, Design
=
=
TWL in Launder provided
=
Flow, Design to Polimer tank
Flow over weir in the Launder to polymer tank
Width of weir , b
Coeff. of discharge, Ce
=
330 m3/hr
330 m3/hr
108.11 m
330.00 m3/hr
=
=
0.40 m
0.864
h=(Q/(0.5445*Ce*(g)^0.5*b))^(2/3)
=
0.2892 m
Free fall considered
=
0.05 m
=
107.77 m
Head over weir=
Therefore,
TWL in Launder to Polymer Tank
Polymer tank to Launder
Flow, Normal
Flow, Design
=
=
TWL in Polymer provided
=
Flow, Design to Polimer tank
Flow over weir in the polymer tank to Launder
Width of weir , b
Coeff. of discharge, Ce
=
330 m3/hr
330 m3/hr
107.77 m
330.00 m3/hr
=
=
6.00 m
0.864
h=(Q/(0.5445*Ce*(g)^0.5*b))^(2/3)
=
0.0475 m
Free fall considered
=
0.05 m
=
107.67 m
Head over weir=
Therefore,
TWL in Launder to Clarifier
Flow from Launder to Clarifier
TWL in the Launder in Polymer tank
=
Flow, Normal
=
314.00 m3/hr
Flow, Design
=
314 m3/hr
Flow, Q=
=
3
7536 m /d
=
314.00 m /h
=
0.0872 m /s
- C= (Hazen-Williams coeff.)
=
100.00
- Pipe diameter d=
=
(350 NB)
107.67 m
3
3
0.350 m
=
350 mm
2
0.096 m
- Cross sectional area, A=
=
- Velocity v=Q/A
=
- Length L=
=
20.42 m
=
0.0038 m/m
0.91 m/s
According to Hazen-Williams formula,
- Slope s=
- Head loss h1= slope x distance
Fittings in pipe line
0.078 m
No.
K
- Check Valves
0
2.00
- Butterfly Valves
0
0.24
- Ball Valves
2
0.05
- 90 deg bend
2
0.45
- 45 deg bend
0
0.35
- Tees (along run)
0
0.40
- Tees (entering run)
0
1.00
- Entrance
0
0.50
- Exit
0
1.00
Total K value of pipe fittings =
=
1.00
Head loss due to fittings in the pipe=h2
=
0.04 m
Total head loss in the pipe = h1+h2
=
0.12 m
Therefore,
TWL in Clarifier
=
107.50 m
(FIXED)
FREE FALL CONSIDERED 100mm
Splitter Box to Launder
Flow, Normal
Flow, Design
=
=
260 m3/hr
260 m3/hr
TWL = TOP OF WATER LEVEL
TWL in Splitter box provided
=
Flow, Design to 2 anoxic tank
Flow over weir in the splitter box to Launder
Width of weir , b
Coeff. of discharge, Ce
=
109.09 m
260.00 m3/hr
=
=
2.50 m
0.864
h=(Q/(0.5445*Ce*(g)^0.5*b))^(2/3)
=
0.0727 m
Free fall considered
=
0.1 m
=
108.92 m
Head over weir=
Therefore,
TWL in Splitter Box to Launder
Launder to Anoxic Tank
Flow, Normal
Flow, Design
=
=
TWL in Launder provided
=
Flow, Design to 2 anoxic tank
Flow over weir in the Launder to 2 anoxic tank
Width of weir , b
Coeff. of discharge, Ce
=
260 m3/hr
260 m3/hr
108.92 m
260.00 m3/hr
=
=
0.40 m
0.864
h=(Q/(0.5445*Ce*(g)^0.5*b))^(2/3)
=
0.2467 m
Free fall considered
=
0.1 m
=
108.58 m
Head over weir=
Therefore,
TWL in Launder to 2 Anoxic tanks
Anoxic Tank to Aeration Tank
Flow, Normal
Flow, Design
=
=
TWL in Anoxic Tank provided
=
Flow, Design to Aeration tank
Flow over weir in the Anoxic tank to aeration
Width of weir , b
Coeff. of discharge, Ce
=
330 m3/hr
330 m3/hr
108.58 m
330.00 m3/hr
=
=
7.00 m
0.864
h=(Q/(0.5445*Ce*(g)^0.5*b))^(2/3)
=
0.0429 m
Free fall considered
=
0.1 m
=
108.43 m
Head over weir=
Therefore,
TWL in Anoxic Tank to Aeration Tank
Aeration Tank to Launder
Flow, Normal
Flow, Design
=
=
TWL in Aeration Tank provided
=
Flow, Design to Polimer tank
Flow over weir in the aeration to Launder
Width of weir , b
Coeff. of discharge, Ce
=
660 m3/hr
660 m3/hr
108.43 m
660.00 m3/hr
=
=
6.00 m
0.864
h=(Q/(0.5445*Ce*(g)^0.5*b))^(2/3)
=
0.0755 m
Free fall considered
=
0.1 m
=
108.26 m
Head over weir=
Therefore,
TWL in Aeration Tank to Launder
Launder To Polymer tank
Flow, Normal
Flow, Design
=
=
TWL in Launder provided
=
Flow, Design to Polimer tank
Flow over weir in the Launder to polymer tank
Width of weir , b
Coeff. of discharge, Ce
=
330 m3/hr
330 m3/hr
108.26 m
330.00 m3/hr
=
=
0.40 m
0.864
h=(Q/(0.5445*Ce*(g)^0.5*b))^(2/3)
=
0.2892 m
Free fall considered
=
0.1 m
=
107.87 m
Head over weir=
Therefore,
TWL in Launder to Polymer Tank
Polymer tank to Launder
Flow, Normal
Flow, Design
=
=
TWL in Polymer provided
=
Flow, Design to Polimer tank
Flow over weir in the polymer tank to Launder
Width of weir , b
Coeff. of discharge, Ce
=
330 m3/hr
330 m3/hr
107.87 m
330.00 m3/hr
=
=
6.00 m
0.864
h=(Q/(0.5445*Ce*(g)^0.5*b))^(2/3)
=
0.0475 m
Free fall considered
=
0.1 m
=
107.72 m
Head over weir=
Therefore,
TWL in Launder to Clarifier
Flow from Launder to Clarifier
TWL in the 5 APIs
=
Flow, Normal
=
314 m3/hr
Flow, Design
=
314 m3/hr
Flow, Q=
=
3
7536 m /d
=
314.00 m /h
=
0.0872 m /s
- C= (Hazen-Williams coeff.)
=
100.00
- Pipe diameter d=
=
(350 NB)
107.72 m
3
3
0.350 m
=
350 mm
2
0.096 m
- Cross sectional area, A=
=
- Velocity v=Q/A
=
- Length L=
=
20.42 m
=
0.0038 m/m
0.91 m/s
According to Hazen-Williams formula,
- Slope s=
- Head loss h1= slope x distance
Fittings in pipe line
0.078 m
No.
K
- Check Valves
0
2.00
- Butterfly Valves
0
0.24
- Ball Valves
2
0.05
- 90 deg bend
2
0.45
- 45 deg bend
0
0.35
- Tees (along run)
0
0.40
- Tees (entering run)
0
1.00
- Entrance
0
0.50
- Exit
0
1.00
Total K value of pipe fittings =
=
1.00
Head loss due to fittings in the pipe=h2
=
0.04 m
Total head loss in the pipe = h1+h2
=
0.12 m
Therefore,
TWL in TPI required
=
107.50 m
(FIXED)
Splitter Box to Launder
Flow, Normal
Flow, Design
=
=
260 m3/hr
260 m3/hr
TWL = TOP OF WATER LEVEL
TWL in Splitter box provided
=
Flow, Design to 2 anoxic tank
Flow over weir in the splitter box to Launder
Width of weir , b
Coeff. of discharge, Ce
=
108.74 m
260.00 m3/hr
=
=
2.50 m
0.864
h=(Q/(0.5445*Ce*(g)^0.5*b))^(2/3)
=
0.0727 m
Free fall considered
=
0.05 m
=
108.62 m
Head over weir=
Therefore,
TWL in Splitter Box to Launder
Launder to Anoxic Tank
Flow, Normal
Flow, Design
=
=
TWL in Launder provided
=
Flow, Design to 2 anoxic tank
Flow over weir in the Launder to 2 anoxic tank
Width of weir , b
Coeff. of discharge, Ce
=
260 m3/hr
260 m3/hr
108.62 m
260.00 m3/hr
=
=
0.40 m
0.864
h=(Q/(0.5445*Ce*(g)^0.5*b))^(2/3)
=
0.2467 m
Free fall considered
=
0.05 m
=
108.33 m
Head over weir=
Therefore,
TWL in Launder to 2 Anoxic tanks
Anoxic Tank to Aeration Tank
Flow, Normal
Flow, Design
=
=
TWL in Anoxic Tank provided
=
Flow, Design to Aeration tank
Flow over weir in the Anoxic tank to aeration
Width of weir , b
Coeff. of discharge, Ce
=
330 m3/hr
330 m3/hr
108.33 m
330.00 m3/hr
=
=
7.00 m
0.864
h=(Q/(0.5445*Ce*(g)^0.5*b))^(2/3)
=
0.0429 m
Free fall considered
=
0.05 m
=
108.23 m
Head over weir=
Therefore,
TWL in Anoxic Tank to Aeration Tank
Aeration Tank to Launder
Flow, Normal
Flow, Design
=
=
TWL in Aeration Tank provided
=
Flow, Design to Polimer tank
Flow over weir in the aeration to Launder
Width of weir , b
Coeff. of discharge, Ce
=
660 m3/hr
660 m3/hr
108.23 m
660.00 m3/hr
=
=
6.00 m
0.864
h=(Q/(0.5445*Ce*(g)^0.5*b))^(2/3)
=
0.0755 m
Free fall considered
=
0.05 m
=
108.11 m
Head over weir=
Therefore,
TWL in Aeration Tank to Launder
Launder To Polymer tank
Flow, Normal
Flow, Design
=
=
TWL in Launder provided
=
Flow, Design to Polimer tank
Flow over weir in the Launder to polymer tank
Width of weir , b
Coeff. of discharge, Ce
=
330 m3/hr
330 m3/hr
108.11 m
330.00 m3/hr
=
=
0.40 m
0.864
h=(Q/(0.5445*Ce*(g)^0.5*b))^(2/3)
=
0.2892 m
Free fall considered
=
0.05 m
=
107.77 m
Head over weir=
Therefore,
TWL in Launder to Polymer Tank
Polymer tank to Launder
Flow, Normal
Flow, Design
=
=
TWL in Polymer provided
=
Flow, Design to Polimer tank
Flow over weir in the polymer tank to Launder
Width of weir , b
Coeff. of discharge, Ce
=
330 m3/hr
330 m3/hr
107.77 m
330.00 m3/hr
=
=
6.00 m
0.864
h=(Q/(0.5445*Ce*(g)^0.5*b))^(2/3)
=
0.0475 m
Free fall considered
=
0.05 m
=
107.67 m
Head over weir=
Therefore,
TWL in Launder to Clarifier
Flow from Launder to Clarifier
TWL in the Launder in Polymer tank
=
Flow, Normal
=
314.00 m3/hr
Flow, Design
=
314 m3/hr
Flow, Q=
=
3
7536 m /d
=
314.00 m /h
=
0.0872 m /s
- C= (Hazen-Williams coeff.)
=
100.00
- Pipe diameter d=
=
(350 NB)
107.67 m
3
3
0.350 m
=
350 mm
2
0.096 m
- Cross sectional area, A=
=
- Velocity v=Q/A
=
- Length L=
=
20.42 m
=
0.0038 m/m
0.91 m/s
According to Hazen-Williams formula,
- Slope s=
- Head loss h1= slope x distance
Fittings in pipe line
0.078 m
No.
K
- Check Valves
0
2.00
- Butterfly Valves
0
0.24
- Ball Valves
2
0.05
- 90 deg bend
2
0.45
- 45 deg bend
0
0.35
- Tees (along run)
0
0.40
- Tees (entering run)
0
1.00
- Entrance
0
0.50
- Exit
0
1.00
Total K value of pipe fittings =
=
1.00
Head loss due to fittings in the pipe=h2
=
0.04 m
Total head loss in the pipe = h1+h2
=
0.12 m
Therefore,
TWL in Clarifier
=
107.50 m
(FIXED)
FREE FALL CONSIDERED 100mm
Splitter Box to Launder
Flow, Normal
Flow, Design
=
=
260 m3/hr
260 m3/hr
TWL = TOP OF WATER LEVEL
TWL in Splitter box provided
=
Flow, Design to 2 anoxic tank
Flow over weir in the splitter box to Launder
Width of weir , b
Coeff. of discharge, Ce
=
109.09 m
260.00 m3/hr
=
=
2.50 m
0.864
h=(Q/(0.5445*Ce*(g)^0.5*b))^(2/3)
=
0.0727 m
Free fall considered
=
0.1 m
=
108.92 m
Head over weir=
Therefore,
TWL in Splitter Box to Launder
Launder to Anoxic Tank
Flow, Normal
Flow, Design
=
=
TWL in Launder provided
=
Flow, Design to 2 anoxic tank
Flow over weir in the Launder to 2 anoxic tank
Width of weir , b
Coeff. of discharge, Ce
=
260 m3/hr
260 m3/hr
108.92 m
260.00 m3/hr
=
=
0.40 m
0.864
h=(Q/(0.5445*Ce*(g)^0.5*b))^(2/3)
=
0.2467 m
Free fall considered
=
0.1 m
=
108.58 m
Head over weir=
Therefore,
TWL in Launder to 2 Anoxic tanks
Anoxic Tank to Aeration Tank
Flow, Normal
Flow, Design
=
=
TWL in Anoxic Tank provided
=
Flow, Design to Aeration tank
Flow over weir in the Anoxic tank to aeration
Width of weir , b
Coeff. of discharge, Ce
=
330 m3/hr
330 m3/hr
108.58 m
330.00 m3/hr
=
=
7.00 m
0.864
h=(Q/(0.5445*Ce*(g)^0.5*b))^(2/3)
=
0.0429 m
Free fall considered
=
0.1 m
=
108.43 m
Head over weir=
Therefore,
TWL in Anoxic Tank to Aeration Tank
Aeration Tank to Launder
Flow, Normal
Flow, Design
=
=
TWL in Aeration Tank provided
=
Flow, Design to Polimer tank
Flow over weir in the aeration to Launder
Width of weir , b
Coeff. of discharge, Ce
=
660 m3/hr
660 m3/hr
108.43 m
660.00 m3/hr
=
=
6.00 m
0.864
h=(Q/(0.5445*Ce*(g)^0.5*b))^(2/3)
=
0.0755 m
Free fall considered
=
0.1 m
=
108.26 m
Head over weir=
Therefore,
TWL in Aeration Tank to Launder
Launder To Polymer tank
Flow, Normal
Flow, Design
=
=
TWL in Launder provided
=
Flow, Design to Polimer tank
Flow over weir in the Launder to polymer tank
Width of weir , b
Coeff. of discharge, Ce
=
330 m3/hr
330 m3/hr
108.26 m
330.00 m3/hr
=
=
0.40 m
0.864
h=(Q/(0.5445*Ce*(g)^0.5*b))^(2/3)
=
0.2892 m
Free fall considered
=
0.1 m
=
107.87 m
Head over weir=
Therefore,
TWL in Launder to Polymer Tank
Polymer tank to Launder
Flow, Normal
Flow, Design
=
=
TWL in Polymer provided
=
Flow, Design to Polimer tank
Flow over weir in the polymer tank to Launder
Width of weir , b
Coeff. of discharge, Ce
=
330 m3/hr
330 m3/hr
107.87 m
330.00 m3/hr
=
=
6.00 m
0.864
h=(Q/(0.5445*Ce*(g)^0.5*b))^(2/3)
=
0.0475 m
Free fall considered
=
0.1 m
=
107.72 m
Head over weir=
Therefore,
TWL in Launder to Clarifier
Flow from Launder to Clarifier
TWL in the 5 APIs
=
Flow, Normal
=
314 m3/hr
Flow, Design
=
314 m3/hr
Flow, Q=
=
3
7536 m /d
=
314.00 m /h
=
0.0872 m /s
- C= (Hazen-Williams coeff.)
=
100.00
- Pipe diameter d=
=
(350 NB)
107.72 m
3
3
0.350 m
=
350 mm
2
0.096 m
- Cross sectional area, A=
=
- Velocity v=Q/A
=
- Length L=
=
20.42 m
=
0.0038 m/m
0.91 m/s
According to Hazen-Williams formula,
- Slope s=
- Head loss h1= slope x distance
Fittings in pipe line
0.078 m
No.
K
- Check Valves
0
2.00
- Butterfly Valves
0
0.24
- Ball Valves
2
0.05
- 90 deg bend
2
0.45
- 45 deg bend
0
0.35
- Tees (along run)
0
0.40
- Tees (entering run)
0
1.00
- Entrance
0
0.50
- Exit
0
1.00
Total K value of pipe fittings =
=
1.00
Head loss due to fittings in the pipe=h2
=
0.04 m
Total head loss in the pipe = h1+h2
=
0.12 m
Therefore,
TWL in TPI required
=
107.50 m
(FIXED)
