Typical Procal Template

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FREE FALL CONSIDERED 50mm
Splitter Box to Launder
Flow, Normal
Flow, Design

=
=

260 m3/hr
260 m3/hr

TWL = TOP OF WATER LEVEL

TWL in Splitter box provided

=

Flow, Design to 2 anoxic tank
Flow over weir in the splitter box to Launder
Width of weir , b
Coeff. of discharge, Ce

=

108.74 m
260.00 m3/hr

=
=

2.50 m
0.864

h=(Q/(0.5445*Ce*(g)^0.5*b))^(2/3)

=

0.0727 m

Free fall considered

=

0.05 m

=

108.62 m

Head over weir=

Therefore,

TWL in Splitter Box to Launder

Launder to Anoxic Tank
Flow, Normal
Flow, Design

=
=

TWL in Launder provided

=

Flow, Design to 2 anoxic tank
Flow over weir in the Launder to 2 anoxic tank
Width of weir , b
Coeff. of discharge, Ce

=

260 m3/hr
260 m3/hr

108.62 m
260.00 m3/hr

=
=

0.40 m
0.864

h=(Q/(0.5445*Ce*(g)^0.5*b))^(2/3)

=

0.2467 m

Free fall considered

=

0.05 m

=

108.33 m

Head over weir=

Therefore,

TWL in Launder to 2 Anoxic tanks

Anoxic Tank to Aeration Tank
Flow, Normal
Flow, Design

=
=

TWL in Anoxic Tank provided

=

Flow, Design to Aeration tank
Flow over weir in the Anoxic tank to aeration
Width of weir , b
Coeff. of discharge, Ce

=

330 m3/hr
330 m3/hr

108.33 m
330.00 m3/hr

=
=

7.00 m
0.864

h=(Q/(0.5445*Ce*(g)^0.5*b))^(2/3)

=

0.0429 m

Free fall considered

=

0.05 m

=

108.23 m

Head over weir=

Therefore,

TWL in Anoxic Tank to Aeration Tank

Aeration Tank to Launder
Flow, Normal
Flow, Design

=
=

TWL in Aeration Tank provided

=

Flow, Design to Polimer tank
Flow over weir in the aeration to Launder
Width of weir , b
Coeff. of discharge, Ce

=

660 m3/hr
660 m3/hr

108.23 m
660.00 m3/hr

=
=

6.00 m
0.864

h=(Q/(0.5445*Ce*(g)^0.5*b))^(2/3)

=

0.0755 m

Free fall considered

=

0.05 m

=

108.11 m

Head over weir=

Therefore,

TWL in Aeration Tank to Launder

Launder To Polymer tank
Flow, Normal
Flow, Design

=
=

TWL in Launder provided

=

Flow, Design to Polimer tank
Flow over weir in the Launder to polymer tank
Width of weir , b
Coeff. of discharge, Ce

=

330 m3/hr
330 m3/hr

108.11 m
330.00 m3/hr

=
=

0.40 m
0.864

h=(Q/(0.5445*Ce*(g)^0.5*b))^(2/3)

=

0.2892 m

Free fall considered

=

0.05 m

=

107.77 m

Head over weir=

Therefore,

TWL in Launder to Polymer Tank

Polymer tank to Launder
Flow, Normal
Flow, Design

=
=

TWL in Polymer provided

=

Flow, Design to Polimer tank
Flow over weir in the polymer tank to Launder
Width of weir , b
Coeff. of discharge, Ce

=

330 m3/hr
330 m3/hr

107.77 m
330.00 m3/hr

=
=

6.00 m
0.864

h=(Q/(0.5445*Ce*(g)^0.5*b))^(2/3)

=

0.0475 m

Free fall considered

=

0.05 m

=

107.67 m

Head over weir=

Therefore,

TWL in Launder to Clarifier

Flow from Launder to Clarifier
TWL in the Launder in Polymer tank

=

Flow, Normal

=

314.00 m3/hr

Flow, Design

=

314 m3/hr

Flow, Q=

=

3
7536 m /d

=

314.00 m /h

=

0.0872 m /s

- C= (Hazen-Williams coeff.)

=

100.00

- Pipe diameter d=

=

(350 NB)

107.67 m

3
3

0.350 m

=

350 mm
2
0.096 m

- Cross sectional area, A=

=

- Velocity v=Q/A

=

- Length L=

=

20.42 m

=

0.0038 m/m

0.91 m/s

According to Hazen-Williams formula,
- Slope s=
- Head loss h1= slope x distance
Fittings in pipe line

0.078 m
No.

K

- Check Valves

0

2.00

- Butterfly Valves

0

0.24

- Ball Valves

2

0.05

- 90 deg bend

2

0.45

- 45 deg bend

0

0.35

- Tees (along run)

0

0.40

- Tees (entering run)

0

1.00

- Entrance

0

0.50

- Exit

0

1.00

Total K value of pipe fittings =

=

1.00

Head loss due to fittings in the pipe=h2

=

0.04 m

Total head loss in the pipe = h1+h2

=

0.12 m

Therefore,

TWL in Clarifier

=

107.50 m

(FIXED)

FREE FALL CONSIDERED 100mm
Splitter Box to Launder
Flow, Normal
Flow, Design

=
=

260 m3/hr
260 m3/hr

TWL = TOP OF WATER LEVEL

TWL in Splitter box provided

=

Flow, Design to 2 anoxic tank
Flow over weir in the splitter box to Launder
Width of weir , b
Coeff. of discharge, Ce

=

109.09 m
260.00 m3/hr

=
=

2.50 m
0.864

h=(Q/(0.5445*Ce*(g)^0.5*b))^(2/3)

=

0.0727 m

Free fall considered

=

0.1 m

=

108.92 m

Head over weir=

Therefore,

TWL in Splitter Box to Launder

Launder to Anoxic Tank
Flow, Normal
Flow, Design

=
=

TWL in Launder provided

=

Flow, Design to 2 anoxic tank
Flow over weir in the Launder to 2 anoxic tank
Width of weir , b
Coeff. of discharge, Ce

=

260 m3/hr
260 m3/hr

108.92 m
260.00 m3/hr

=
=

0.40 m
0.864

h=(Q/(0.5445*Ce*(g)^0.5*b))^(2/3)

=

0.2467 m

Free fall considered

=

0.1 m

=

108.58 m

Head over weir=

Therefore,

TWL in Launder to 2 Anoxic tanks

Anoxic Tank to Aeration Tank
Flow, Normal
Flow, Design

=
=

TWL in Anoxic Tank provided

=

Flow, Design to Aeration tank
Flow over weir in the Anoxic tank to aeration
Width of weir , b
Coeff. of discharge, Ce

=

330 m3/hr
330 m3/hr

108.58 m
330.00 m3/hr

=
=

7.00 m
0.864

h=(Q/(0.5445*Ce*(g)^0.5*b))^(2/3)

=

0.0429 m

Free fall considered

=

0.1 m

=

108.43 m

Head over weir=

Therefore,

TWL in Anoxic Tank to Aeration Tank

Aeration Tank to Launder
Flow, Normal
Flow, Design

=
=

TWL in Aeration Tank provided

=

Flow, Design to Polimer tank
Flow over weir in the aeration to Launder
Width of weir , b
Coeff. of discharge, Ce

=

660 m3/hr
660 m3/hr

108.43 m
660.00 m3/hr

=
=

6.00 m
0.864

h=(Q/(0.5445*Ce*(g)^0.5*b))^(2/3)

=

0.0755 m

Free fall considered

=

0.1 m

=

108.26 m

Head over weir=

Therefore,

TWL in Aeration Tank to Launder

Launder To Polymer tank
Flow, Normal
Flow, Design

=
=

TWL in Launder provided

=

Flow, Design to Polimer tank
Flow over weir in the Launder to polymer tank
Width of weir , b
Coeff. of discharge, Ce

=

330 m3/hr
330 m3/hr

108.26 m
330.00 m3/hr

=
=

0.40 m
0.864

h=(Q/(0.5445*Ce*(g)^0.5*b))^(2/3)

=

0.2892 m

Free fall considered

=

0.1 m

=

107.87 m

Head over weir=

Therefore,

TWL in Launder to Polymer Tank

Polymer tank to Launder
Flow, Normal
Flow, Design

=
=

TWL in Polymer provided

=

Flow, Design to Polimer tank
Flow over weir in the polymer tank to Launder
Width of weir , b
Coeff. of discharge, Ce

=

330 m3/hr
330 m3/hr

107.87 m
330.00 m3/hr

=
=

6.00 m
0.864

h=(Q/(0.5445*Ce*(g)^0.5*b))^(2/3)

=

0.0475 m

Free fall considered

=

0.1 m

=

107.72 m

Head over weir=

Therefore,

TWL in Launder to Clarifier

Flow from Launder to Clarifier
TWL in the 5 APIs

=

Flow, Normal

=

314 m3/hr

Flow, Design

=

314 m3/hr

Flow, Q=

=

3
7536 m /d

=

314.00 m /h

=

0.0872 m /s

- C= (Hazen-Williams coeff.)

=

100.00

- Pipe diameter d=

=

(350 NB)

107.72 m

3
3

0.350 m

=

350 mm
2
0.096 m

- Cross sectional area, A=

=

- Velocity v=Q/A

=

- Length L=

=

20.42 m

=

0.0038 m/m

0.91 m/s

According to Hazen-Williams formula,
- Slope s=
- Head loss h1= slope x distance
Fittings in pipe line

0.078 m
No.

K

- Check Valves

0

2.00

- Butterfly Valves

0

0.24

- Ball Valves

2

0.05

- 90 deg bend

2

0.45

- 45 deg bend

0

0.35

- Tees (along run)

0

0.40

- Tees (entering run)

0

1.00

- Entrance

0

0.50

- Exit

0

1.00

Total K value of pipe fittings =

=

1.00

Head loss due to fittings in the pipe=h2

=

0.04 m

Total head loss in the pipe = h1+h2

=

0.12 m

Therefore,

TWL in TPI required

=

107.50 m

(FIXED)

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